NDA Chemistry
Chemical Bonding States — Quiz
20 Questions · No Negative Marking
Question 1
According to VSEPR theory, the shape of SF₆ (6 bonding pairs, 0 lone pairs) is:
AOctahedral (90° bond angles)
BTrigonal bipyramidal
CSquare planar
DTetrahedral
Question 2
In the valence bond (VB) theory, hybridisation of water (H₂O) is sp³ yet the bond angle is 104.5° rather than 109.5°. This is because:
AH atoms are too small to repel each other properly
BLone pair-lone pair repulsion > lone pair-bond pair > bond pair-bond pair
CThe O-H bond is polar, causing bond angle reduction
Dsp³ hybridisation always gives angles less than 109.5°
Question 3
The bond order in molecular orbital (MO) theory is defined as (bonding electrons - antibonding electrons)/2. The bond order of O₂ is:
A1 (single bond)
B2 (double bond — from MO theory
C3 (triple bond)
D0 (O₂ does not exist as a stable molecule)
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