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PC11 — Semiconductors & Electronic Devices

📖 PC11  ·  CDS General Science — Physics

This chapter covers the physics underlying all modern electronic devices — from transistors to logic gates. CDS questions focus on the distinction between conductors, insulators, and semiconductors; the p-n junction diode; and basic logic gates with truth tables. While lower-weightage, when questions appear they are often straightforward and scoring.

📌 CDS focuses on: Conductors vs semiconductors vs insulators (energy band); intrinsic vs extrinsic semiconductors (n-type, p-type); p-n junction diode — forward and reverse bias; rectification; basic logic gates (AND, OR, NOT) and their truth tables; NAND and NOR as universal gates.

1. Conductors, Semiconductors & Insulators

1.1
Energy Band Theory — Why Materials Conduct Differently
Energy Band Diagrams — Conductor, Semiconductor, Insulator CONDUCTOR (e.g. copper, silver) Valence Band Conduction Band Overlapping! Bands overlap → electrons flow freely Resistivity: very low SEMICONDUCTOR (e.g. silicon, germanium) Valence Band Small gap (~1 eV) Conduction Band Small gap → some electrons can jump Partial conduction INSULATOR (e.g. diamond, glass) Valence Band Large forbidden gap (~5–10 eV) Conduction Band Large gap → electrons cannot cross → no flow
Fig. 1 — Energy band theory. Conductors have overlapping bands (electrons flow freely). Semiconductors have a small gap (partial conduction). Insulators have a large gap (no conduction under normal conditions).

📍 n-Type Semiconductor

  • Silicon/Germanium doped with pentavalent atoms (Phosphorus, Arsenic, Antimony)
  • Each dopant atom has 5 valence electrons — 4 form bonds, 1 is free
  • Majority carriers: free electrons (negative charge carriers)
  • Minority carriers: holes
  • "n" = negative majority carriers

📍 p-Type Semiconductor

  • Silicon/Germanium doped with trivalent atoms (Boron, Aluminium, Gallium)
  • Each dopant has 3 valence electrons — forms 3 bonds, creates a "hole" (vacancy)
  • Majority carriers: holes (behave like positive charge carriers)
  • Minority carriers: electrons
  • "p" = positive majority carriers

2. p-n Junction Diode

2.1
Forward & Reverse Bias — Rectification
p-n Junction Diode — Forward and Reverse Bias FORWARD BIAS +ve terminal to p, −ve to n → Current flows p n + I flows ✓ Conduction State: ON Depletion layer shrinks → barrier reduced Current flows easily. Forward voltage ~0.7V (Si) REVERSE BIAS +ve to n, −ve to p → No current p n + No current Conduction State: OFF Depletion layer widens → barrier increases No current flows (except tiny leakage current)
Fig. 2 — p-n junction diode: forward bias (p to +, n to −) allows current to flow; reverse bias blocks current. This one-way current flow is used in rectifiers to convert AC to DC.
Rectification: A diode allows current in only one direction. Used in rectifier circuits to convert alternating current (AC) to direct current (DC). Half-wave rectifier: uses one diode — blocks half the AC cycle. Full-wave rectifier: uses four diodes in bridge configuration — converts both halves of AC cycle. All chargers (phone chargers, laptop adapters) contain rectifier circuits.

3. Logic Gates

3.1
Basic & Universal Logic Gates with Truth Tables
The building blocks of all digital circuits — computers, phones, and everything digital
Logic Gates — Symbols, Rules & Truth Tables AND Gate Output = 1 only if ALL inputs = 1 AB Y Y = A · B ABY 000 010 100 111 Output 1 only when A AND B both = 1 OR Gate Output = 1 if ANY input = 1 AB Y Y = A + B ABY 000 011 101 111 Output 0 only when both inputs are 0 NOT Gate Output = inverse of input A Y Y = Ā (NOT A) AY 01 10 Inverts the input Universal Gates: NAND and NOR NAND = NOT + AND (output: 0 only when both inputs are 1). NOR = NOT + OR (output: 1 only when both inputs are 0). Both NAND and NOR are "universal" — any logic circuit can be built using only NAND gates (or only NOR gates).
Fig. 3 — The three basic logic gates with symbols and truth tables. AND: output is 1 only when all inputs are 1. OR: output is 0 only when all inputs are 0. NOT: output is always opposite of input.
📝 CDS PYQ
Semiconductors & Electronics
Q1. A p-n junction diode is forward biased when:
  • (a) p-side to negative and n-side to positive terminal
  • (b) p-side to positive and n-side to negative terminal
  • (c) Both p and n sides to positive terminal
  • (d) No bias is applied
Answer: (b) p-side to positive, n-side to negative terminal
Forward bias: connect the positive terminal of the battery to the p-side and the negative terminal to the n-side. This reduces the potential barrier at the junction, allowing current to flow. In reverse bias (opposite connection), the barrier increases and no significant current flows — only a tiny leakage current. This unidirectional property makes diodes useful as rectifiers.
Q2. The output of a NAND gate is 0 only when:
  • (a) All inputs are 0
  • (b) All inputs are 1
  • (c) At least one input is 1
  • (d) Inputs are different
Answer: (b) All inputs are 1
NAND = NOT + AND. The AND gate gives output 1 only when all inputs are 1. The NOT then inverts this to 0. For any other combination of inputs, AND gives 0, which NOT inverts to 1. So NAND output is 0 ONLY when both inputs are 1; otherwise output is always 1. NAND is a universal gate — all other gates can be built from NAND gates alone.
Q3. n-type semiconductor is formed by adding which type of impurity to silicon?
  • (a) Trivalent (3 valence electrons)
  • (b) Pentavalent (5 valence electrons)
  • (c) Divalent (2 valence electrons)
  • (d) Monovalent (1 valence electron)
Answer: (b) Pentavalent
Adding a pentavalent atom (5 valence electrons — e.g. phosphorus, arsenic, antimony) to silicon (tetravalent, 4 valence electrons) creates an n-type semiconductor. Four of the five valence electrons form bonds with silicon; the fifth is a free electron — the majority charge carrier. For p-type, trivalent atoms (e.g. boron) are added, creating "holes" (missing electrons) as majority carriers.

📚 Formula Sheet & Key Facts — PC11

📍 Semiconductor Types
  • n-type: pentavalent dopant; free electrons
  • p-type: trivalent dopant; holes
  • Silicon band gap ≈ 1.1 eV
  • Ge band gap ≈ 0.7 eV
  • R decreases on heating (unlike metals)
⚡ Diode
  • Forward bias: p(+), n(−) → current flows
  • Reverse bias: p(−), n(+) → no current
  • Si forward voltage ≈ 0.7 V
  • Rectifier: converts AC to DC
  • Half-wave: 1 diode; Full-wave: 4 diodes
📋 Logic Gates
  • AND: Y=A·B; output 1 only if both 1
  • OR: Y=A+B; output 0 only if both 0
  • NOT: Y=Ā; inverts input
  • NAND: output 0 only if both inputs 1
  • NOR: output 1 only if both inputs 0
🔋 Universal Gates
  • NAND and NOR are universal gates
  • Any circuit can be made from NAND alone
  • Any circuit can be made from NOR alone
  • Transistor: amplifier or switch
  • BJT: NPN or PNP type

⚡ Quick Revision — PC11

📍 Semiconductor Basics
  • Conductor > Semiconductor > Insulator (conductivity)
  • n-type: electrons; p-type: holes
  • Pentavalent → n-type doping
  • Trivalent → p-type doping
  • R decreases with temperature (unlike metals)
⚡ Diode Facts
  • Forward: p(+) → current flows
  • Reverse: no current flows
  • Uses: rectifier, LED, solar cell, detector
  • Rectifier: AC to DC conversion
  • Si diode: ~0.7V forward drop
📋 Logic Gates Quick
  • AND: output 1 only when all inputs = 1
  • OR: output 0 only when all inputs = 0
  • NOT: output = opposite of input
  • NAND = NOT(AND); NOR = NOT(OR)
  • NAND and NOR: both universal gates
🚨 CDS Traps
  • n-type: pentavalent (NOT trivalent)
  • p-type: trivalent (NOT pentavalent)
  • Forward bias: p to +ve terminal
  • NAND output 0: only when both inputs 1
  • NOR output 1: only when both inputs 0

📝 Practice Exercise

E-01
Two inputs A=1, B=0 are fed into a NOR gate. The output is:
  • (a) 1
  • (b) 0
  • (c) Depends on the circuit
  • (d) Undefined
E-02
Silicon is a semiconductor. Its electrical conductivity:
  • (a) Increases with temperature
  • (b) Decreases with temperature
  • (c) Remains constant
  • (d) Only changes above 500°C
E-03
Which gate gives an output of 1 only when all inputs are 1?
  • (a) OR
  • (b) NOT
  • (c) NAND
  • (d) AND
E-04
A full-wave rectifier uses how many diodes?
  • (a) 1
  • (b) 2
  • (c) 4
  • (d) 8
Answers:  E-01: (b) 0 [NOR = NOT(OR); OR(1,0)=1; NOT(1)=0]  |  E-02: (a) Increases — more electron-hole pairs form at higher temp, increasing conductivity (opposite to metals)  |  E-03: (d) AND gate — output is 1 only when all inputs are 1  |  E-04: (c) 4 diodes — bridge rectifier uses 4 diodes in a bridge configuration to utilise both halves of AC
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