Mathematics · Module MAT01
Number System —
Types, Properties & Tricks
From classification of numbers and divisibility rules to LCM, HCF, remainders, unit digits, and surds — every concept tested in CDS, NDA, and AFCAT.
Foundation → Advanced
CDS · NDA · AFCAT
25 Practice Questions
Mathematics MAT01
Covers: Classification of Numbers, Divisibility Rules, LCM & HCF, Prime Numbers & Factors, Unit Digit & Cyclicity, Remainders, Fractions & Decimals, Surds & Indices, Number Series & Formulae — all topics tested in defence entrance exams.
Section 1 — Classification of Numbers
🔢
Types of Numbers — Complete Hierarchy
Natural · Whole · Integer · Rational · Irrational · Real
▾
| Type | Definition | Examples |
| Natural (N) | Counting numbers starting from 1 | 1, 2, 3, 4 … |
| Whole (W) | Natural numbers + zero | 0, 1, 2, 3 … |
| Integers (Z) | Whole + negative numbers | … −2, −1, 0, 1, 2 … |
| Rational (Q) | Expressible as p/q, q ≠ 0 | ½, −3, 0.75, 0.33… |
| Irrational | Non-terminating, non-repeating | √2, π, e, √3 |
| Real (R) | All rational + irrational | Any point on number line |
Key Subset Relationships
- N ⊂ W ⊂ Z ⊂ Q ⊂ R — every natural number is also whole, integer, rational, and real
- 0 is whole but NOT natural · −5 is integer but NOT whole or natural
- Every integer is rational — e.g., −3 = −3/1
- π is irrational — 22/7 is only a rational approximation, not equal to π
- √4 = 2 is rational; √2 is irrational — perfect squares have rational roots
Even, Odd, Prime, Composite — Critical Definitions
- Even: divisible by 2 → 0, 2, 4, 6 … Note: 0 is even
- Prime: exactly 2 factors (1 and itself) → 2, 3, 5, 7, 11 … 1 is NOT prime
- Composite: more than 2 factors → 4, 6, 8, 9 … 1 is neither prime nor composite
- Co-prime: two numbers whose HCF = 1 — need NOT be individually prime (e.g., 8 and 15)
- 2 is the only even prime number
⚑ Classification Traps
- 1 is neither prime nor composite — the most common mistake
- 0 is even, whole but NOT natural
- 22/7 ≠ π — 22/7 is rational; π is irrational
- Every prime > 2 is odd, but not every odd is prime (e.g., 9 = 3 × 3)
Section 2 — Divisibility Rules
÷
Divisibility Rules — 2 through 13
Check divisibility in seconds without long division
▾
| Divisor | Rule | Example |
| 2 | Last digit even (0,2,4,6,8) | 348 ✓ |
| 3 | Sum of digits divisible by 3 | 123: 1+2+3=6 ✓ |
| 4 | Last 2 digits divisible by 4 | 1732: 32÷4=8 ✓ |
| 5 | Last digit is 0 or 5 | 445, 230 ✓ |
| 6 | Divisible by BOTH 2 AND 3 | 126 ✓ |
| 8 | Last 3 digits divisible by 8 | 1256: 256÷8=32 ✓ |
| 9 | Sum of digits divisible by 9 | 729: 7+2+9=18 ✓ |
| 11 | (Sum of odd-position digits) − (sum of even-position digits) = 0 or multiple of 11 | 121: (1+1)−2=0 ✓ |
| 12 | Divisible by BOTH 3 AND 4 | 144 ✓ |
⚑ Divisibility Traps
- Div by 6 = div by 2 AND div by 3 — BOTH conditions must hold simultaneously
- Div by 4 → check LAST TWO digits (not digit sum)
- Div by 8 → check LAST THREE digits
- Divisible by 9 → also divisible by 3, but NOT vice versa
Section 3 — LCM & HCF
🔄
HCF & LCM — Methods, Formulae & Applications
Highest Common Factor · Lowest Common Multiple · word problems
▾
Core Definitions & Key Formula
- HCF (GCD): Largest number that divides all given numbers exactly
- LCM: Smallest number divisible by all given numbers
- Key formula (two numbers only): HCF × LCM = Product of the two numbers
- HCF always ≤ smallest number · LCM always ≥ largest number
- HCF of fractions = HCF of numerators ÷ LCM of denominators
- LCM of fractions = LCM of numerators ÷ HCF of denominators
Exam-Ready Word Problem Patterns
- Bells/signals ringing together: answer = LCM of time intervals
- Largest square tile for a rectangular floor: answer = HCF of dimensions
- Least number divisible by x, y, z leaving remainder r: LCM(x,y,z) + r
- Largest number dividing a, b, c with same remainder: HCF of all pairwise differences
- Largest number dividing a, b, c leaving remainders p, q, r: HCF(a−p, b−q, c−r)
⚑ LCM/HCF Traps
- HCF × LCM = product formula applies to EXACTLY TWO numbers only
- HCF of fractions uses LCM of denominators in the denominator — not HCF
Section 4 — Primes & Number of Factors
🔎
Prime Numbers, Factorisation & Counting Divisors
25 primes below 100 · testing primality · factor formula
▾
All 25 Primes up to 100
- 1–20: 2, 3, 5, 7, 11, 13, 17, 19
- 21–50: 23, 29, 31, 37, 41, 43, 47
- 51–100: 53, 59, 61, 67, 71, 73, 79, 83, 89, 97
Number of Factors Formula
If N = 2a × 3b × 5c × … then:
- Total factors = (a+1)(b+1)(c+1)…
- Example: 360 = 2³ × 3² × 5¹ → factors = (3+1)(2+1)(1+1) = 4×3×2 = 24
- Perfect square has an odd number of total factors
- To test if n is prime: check divisibility by all primes up to √n
Section 5 — Unit Digit & Cyclicity
⁰
Unit Digit of Powers — Cyclicity Method
Find the last digit of any power in under 10 seconds
▾
| Unit digit of base | Cycle (successive powers) | Period |
| 0, 1, 5, 6 | Always the same unit digit | 1 |
| 4 | 4, 6, 4, 6 … | 2 |
| 9 | 9, 1, 9, 1 … | 2 |
| 2 | 2, 4, 8, 6, 2, 4, 8, 6 … | 4 |
| 3 | 3, 9, 7, 1, 3, 9, 7, 1 … | 4 |
| 7 | 7, 9, 3, 1, 7, 9, 3, 1 … | 4 |
| 8 | 8, 4, 2, 6, 8, 4, 2, 6 … | 4 |
4-Step Method
- Step 1: Identify the unit digit of the base
- Step 2: Find the cycle length for that digit
- Step 3: Divide the power by the cycle length → find the remainder
- Step 4: That remainder's position in the cycle = unit digit. If remainder = 0, use the last value in the cycle
- Example — unit digit of 7⁵²: cycle (7,9,3,1), period 4. 52÷4 = rem 0 → last in cycle = 1
- Example — unit digit of 2⁸³: cycle (2,4,8,6), period 4. 83÷4 = rem 3 → 3rd in cycle = 8
Section 6 — Remainders
%
Remainder Rules & Pattern Method
Key properties · pattern/cyclicity · Wilson's theorem
▾
Fundamental Properties
- R[(a+b) ÷ n] = R[ R(a÷n) + R(b÷n) ] ÷ n
- R[(a×b) ÷ n] = R[ R(a÷n) × R(b÷n) ] ÷ n
- Remainder when 10ⁿ ÷ 9 = always 1
- n! ÷ p = 0 (remainder zero) when p is prime and p ≤ n
- Wilson's Theorem: If p is prime → (p−1)! ≡ −1 (mod p), i.e., remainder = p−1
- aⁿ + bⁿ is divisible by (a+b) when n is odd
- aⁿ − bⁿ is divisible by (a−b) for all natural n
Pattern Method — Most Used in Exams
- Find remainder of 2¹⁰⁰ ÷ 3: pattern: 2¹→2, 2²→1, 2³→2, cycle of 2. 100 is even → rem = 1
- Find unit digit = find remainder ÷ 10 (same operation, different framing)
- Remainder when (1!+2!+3!+…+100!) ÷ 10: n! for n≥5 has factors 2 and 5 so ends in 0. Only first four terms matter: 1+2+6+24 = 33 → remainder = 3
Section 7 — Surds & Indices
√
Laws of Indices & Surd Operations
All index laws · rationalising · comparing surds
▾
Laws of Indices — All Rules
- aᵐ × aⁿ = aᵐ⁺ⁿ
- aᵐ ÷ aⁿ = aᵐ⁻ⁿ
- (aᵐ)ⁿ = aᵐⁿ
- (ab)ⁿ = aⁿbⁿ
- a⁰ = 1 for any a ≠ 0 · 0⁰ is undefined
- a⁻ⁿ = 1/aⁿ · a^(m/n) = ⁿ√(aᵐ)
Surds — Key Operations
- Like surds: same radicand → add/subtract: 3√2 + 5√2 = 8√2
- Unlike surds: cannot simplify: √2 + √3 ≠ √5
- Rationalising: 1/(a−√b) → multiply by (a+√b)/(a+√b); denominator = a²−b
- Comparing surds: make indices equal. ∛2 vs ⁴√3 → ¹²√16 vs ¹²√27 → ⁴√3 > ∛2
⚑ Surds & Indices Traps
- √(a²+b²) ≠ a+b — extremely common error
- √a + √b ≠ √(a+b)
- 0⁰ is undefined — not 1 and not 0
- a⁻¹ = 1/a, NOT −a
Section 8 — Number Series & Key Formulae
📐
Sum Formulae, AP & GP
All standard summation results tested in defence exams
▾
Standard Sum Formulae
- Sum of first n natural numbers: n(n+1)/2
- Sum of first n odd numbers: 1+3+5+…+(2n−1) = n²
- Sum of first n even numbers: 2+4+…+2n = n(n+1)
- Sum of squares: 1²+2²+…+n² = n(n+1)(2n+1)/6
- Sum of cubes: 1³+2³+…+n³ = [n(n+1)/2]²
Arithmetic & Geometric Progressions
- AP nth term: aₙ = a + (n−1)d
- AP Sum: Sₙ = n/2 × [2a + (n−1)d] = n/2 × (first + last)
- GP nth term: aₙ = ar^(n−1)
- GP Sum (finite): Sₙ = a(rⁿ−1)/(r−1) for r ≠ 1
- GP Sum (infinite, |r|<1): S∞ = a/(1−r)
Scan all high-yield Number System formulae and rules before your exam.
🔢 Number Types
- N ⊂ W ⊂ Z ⊂ Q ⊂ R
- 0 = whole, NOT natural · 1 = neither prime nor composite
- 2 = only even prime
- π is irrational · 22/7 is only an approximation
- √4=2 rational · √2 irrational
- Co-prime: HCF=1 (need not be individually prime)
÷ Divisibility Rules
- 2: last digit even · 3: digit sum ÷ 3
- 4: last 2 digits ÷ 4 · 8: last 3 digits ÷ 8
- 9: digit sum ÷ 9 · 5: ends in 0 or 5
- 6 = div by 2 AND 3 · 12 = div by 3 AND 4
- 11: |odd-pos sum − even-pos sum| = 0 or 11
🔄 LCM & HCF
- HCF × LCM = a × b (two numbers only)
- HCF ≤ smallest · LCM ≥ largest
- HCF(fractions) = HCF(num)/LCM(den)
- LCM(fractions) = LCM(num)/HCF(den)
- Bells ring together → LCM of intervals
- Largest tile → HCF of dimensions
- Least no. leaving rem r → LCM + r
⁰ Unit Digit Cycles
- 0,1,5,6 → always same · 4,9 → period 2
- 2: (2,4,8,6) · 3: (3,9,7,1) · period 4
- 7: (7,9,3,1) · 8: (8,4,2,6) · period 4
- Divide power by period → find remainder → position in cycle
- If remainder = 0 → use last value of cycle
√ Surds & Indices
- aᵐ·aⁿ = aᵐ⁺ⁿ · (aᵐ)ⁿ = aᵐⁿ
- a⁰ = 1 (a≠0) · 0⁰ = undefined
- a^(m/n) = ⁿ√aᵐ · a⁻ⁿ = 1/aⁿ
- √a·√b = √(ab) · √a+√b ≠ √(a+b)
- Rationalise: × conjugate; denom = a²−b
- Compare: make indices equal, compare bases
📐 Sum Formulae
- Σn = n(n+1)/2
- Σ odd (n terms) = n²
- Σ even (n terms) = n(n+1)
- Σn² = n(n+1)(2n+1)/6
- Σn³ = [n(n+1)/2]²
- AP: aₙ = a+(n−1)d · Sₙ = n/2(a+l)
- GP∞: S = a/(1−r), |r|<1
% Remainders
- R(a+b)÷n = R[R(a)+R(b)]÷n
- 10ⁿ ÷ 9 → remainder always 1
- n! ÷ p (prime ≤ n) → remainder 0
- Wilson: (p−1)! mod p = p−1 for prime p
- aⁿ+bⁿ div by (a+b) when n is odd
- aⁿ−bⁿ always div by (a−b)
🔎 Primes & Factors
- Primes to 50: 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47
- Test: divide by primes up to √n
- N=2ᵃ·3ᵇ·5ᶜ → factors = (a+1)(b+1)(c+1)
- Perfect square ↔ odd number of total factors
- Twin primes: (3,5)(5,7)(11,13)(17,19)(29,31)